document.write( "Question 72630: Solve and show work.
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Algebra.Com's Answer #51930 by Edwin McCravy(20086)\"\" \"About 
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Solve and show work.\r\n" );
document.write( "The length of a rectangle is 2 cm more \r\n" );
document.write( "than twice its width.  If the perimeter \r\n" );
document.write( "of the rectangle is 52 cm, find the \r\n" );
document.write( "dimensions of the rectangle.\r\n" );
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document.write( "Translate \"The length of a rectangle is \r\n" );
document.write( "2 cm more than twice its width\" as\r\n" );
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document.write( "\"Write down twice the width, 2w, and then \r\n" );
document.write( "add 2 to make it 2 cm more, getting\r\n" );
document.write( "2w + 2\".  So LENGTH = 2w+2\r\n" );
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document.write( "Draw a rectangle and place w\r\n" );
document.write( "on the widths and 2w+2 on the lengths: \r\n" );
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document.write( "       |       2w+2        |\r\n" );
document.write( "      w|                   |w\r\n" );
document.write( "       |                   |\r\n" );
document.write( "       |___________________| \r\n" );
document.write( "               2w+2  \r\n" );
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document.write( "Perimeter means add all the sides all the way around \r\n" );
document.write( "the rectangle:\r\n" );
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document.write( "Perimeter = Left side + Top side + Right side + Bottom side\r\n" );
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document.write( "   52     =      w    +    2w+2  +      w     +    2w+2\r\n" );
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document.write( "       52 = w + 2w + 2 + w + 2w + 2\r\n" );
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document.write( "Solve that and get w = 8 \r\n" );
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document.write( "Now find the length by substituting in\r\n" );
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document.write( "LENGTH = 2w+2 \r\n" );
document.write( "LENGTH = 2(8) + 2 = 16+2 = 18\r\n" );
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document.write( "So the length = 18 cm and the width is 8 cm.\r\n" );
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document.write( "Edwin

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