document.write( "Question 861835: The width of a rectangle is 5 feet less than its length. The perimeter of the rectangle is 70 feet. Find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #519297 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
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\n" ); document.write( "P = 2L + 2w = 70ft
\n" ); document.write( "0r L + w = 35ft
\n" ); document.write( " L + (L-5) - 35 Note:The width of a rectangle is 5 feet less than its length.
\n" ); document.write( " 2L = 40
\n" ); document.write( " L = 20ft and w = 15ft \"20-5%29\" \n" ); document.write( "
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