document.write( "Question 861798: A number consists of two digits.
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document.write( "When the number is divided by the units digit, the answer is 3.
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document.write( "If the digits are reversed, the new number exceeds the original number by 36.
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document.write( "Determine the original number. \n" );
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Algebra.Com's Answer #519265 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x=10a+b, \n" ); document.write( "x/b=3, \n" ); document.write( "y=10b+a, \n" ); document.write( "y-x=36 \n" ); document.write( "a = 1, b = 5, \n" ); document.write( "x = 15, y = 51 \n" ); document.write( "check \n" ); document.write( "15/5=3 \n" ); document.write( "51-15=36 \n" ); document.write( "ok\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Just for fun how could you solve this by using logic and not algebra? \n" ); document.write( "We are looking for a 2 digit product of 3 and a single digit from 0 to 9. \n" ); document.write( "The factor is also the second digit \n" ); document.write( "3*0=0 \n" ); document.write( "3*1=3 \n" ); document.write( "3*2=6 \n" ); document.write( "3*3=9 \n" ); document.write( "Now we have reached two digit products. \n" ); document.write( "3*4=12 \n" ); document.write( "3*5=15 \n" ); document.write( "3*6=18 \n" ); document.write( "3*7=21 \n" ); document.write( "3*8=24 \n" ); document.write( "3*9=27\r \n" ); document.write( "\n" ); document.write( "Only 3*5=15 satisfies the conditions \n" ); document.write( "15 reversed =51 \n" ); document.write( "51-15=36 \n" ); document.write( "Success! \n" ); document.write( " |