document.write( "Question 861660: y varies directly as x and inversely as the square of z. y=24 when x=12 and z=2. Find y when x=64 and z=4. \r
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document.write( "thank you so much! \n" );
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Algebra.Com's Answer #519228 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! y=kx/z^2 \n" ); document.write( "24=2k/4 \n" ); document.write( "24=k/2 \n" ); document.write( "k=48 \n" ); document.write( "y=48x/z^2 \n" ); document.write( "y=48*64/16 \n" ); document.write( "y=192\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |