document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=861750>Question 861750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a conical block of silver has a height of 16c, and a base radius of 12cm.how many coins 1/6cm thick and 1 1/2 cm in diameter can be made by melting the silver?\r<BR>\n" );
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document.write( "The answer at the back of the book is 8192\r<BR>\n" );
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document.write( "please explain in detail and give the solution with steps. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #519210 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=519210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Volume of cone = 1/3 * pi * r^2*h\r<BR>\n" );
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document.write( "=1/3 *pi*12^2*16\r<BR>\n" );
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document.write( "=768 pi\r<BR>\n" );
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document.write( "Volume of coin = pi r^2 h\r<BR>\n" );
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document.write( "=pi*(3/4)^2*(1/6)\r<BR>\n" );
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document.write( "=0.09 pi\r<BR>\n" );
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document.write( "Number of coins = Volume of cone/volume of coin\r<BR>\n" );
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document.write( "=768 pi/0.09 pi\r<BR>\n" );
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document.write( "= 8192 coins\r<BR>\n" );
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document.write( " </SPAN>\n" );
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