document.write( "Question 861713: Hello I am so confused on how to solve this word problem\r
\n" ); document.write( "\n" ); document.write( "How many liters of a 70% acid solution must be mixed with a 20% acid solution to get 500 L of a 60% acid solution?\r
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Algebra.Com's Answer #519175 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Percent ---------------- quantity
\n" ); document.write( "Acid type I 70.00% ---------------- x liters
\n" ); document.write( "Acid type II 20.00% ------ 500 - x liters
\n" ); document.write( "Mixture 60.00% ---------------- 500
\n" ); document.write( "Total 500 liters
\n" ); document.write( "70.00% x + 20.00% ( 500 - x ) = 60.00% * 500
\n" ); document.write( "70 x + 20 ( 500 - x ) = 30000
\n" ); document.write( "70 x + 10000 - 20 x = 30000
\n" ); document.write( "70 x - 20 x = 30000 - -10000
\n" ); document.write( "50 x = 20000
\n" ); document.write( "/ 50
\n" ); document.write( " x = 400 liters 70.00% Acid type I
\n" ); document.write( " 100 liters 20.00% Acid type II
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\n" ); document.write( "m.ananth@hotmail.ca
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