document.write( "Question 861676: a radiator contains 6 L of a 44% antifreeze mixture. how much pure antifreeze should be added to make a mixture that is 52% antifreeze. \n" ); document.write( "

Algebra.Com's Answer #519171 by richwmiller(17219) $\"\"$ $\"About$

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.44*6+x=.52*(6+x)
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