document.write( "Question 861680: A rectangle is drawn so that the width is 4 feet shorter than the length. The area of the rectangle is 12 square feet. Find the length of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #519167 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Common enough to be worth generalizing.\r \n" ); document.write( "\n" ); document.write( "width w, length L. \n" ); document.write( "Width is soe k feet shorter than length, or w=L-k. \n" ); document.write( "Area is given, and may be called A. \n" ); document.write( "The unknown variables are L and w. \n" ); document.write( "(A=12 and k=4).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "Note that your given values for area and for k may render the quadratic equation in L as factorable. In GENERAL, you cannot rely on factorizability. \n" ); document.write( "General Solution to Quadratic Equation gives for L, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can substitute the values for A and k to compute L. \n" ); document.write( " |