document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=861626>Question 861626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that the \"20\" in Figure 9.23 is actually 16. Use this fact to find both the perimeter and area of the isosceles triangle in Figure 9.23. (The base is 10 units, and the height is 16 units.) Suggestion: First use the Pythagorean theorem to find the lengths of the unknown sides of the triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #519143 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=519143\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm a little confused as to why your question says \"Assume that the 20 is actually 16\" but whatever.\r<BR>\n" );
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document.write( "Area = (1/2)(10)(16) = 80 units^2<BR>\n" );
document.write( "Perimeter = 10 + 16 + sqrt(10^2 + 16^2) units </SPAN>\n" );
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