document.write( "Question 72588: (125/8X to the 12 power ) all that raised to a -2/3 power. So 125 over 8X to the 12th power and all of that raised to the -2/3 power
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document.write( "I tried 125 to the -2/3 over 8 to the -2/3 (times) 8X to the -8 and got 125 over 8X to the -8.then fliped it because it is a negative exponent which would be 8X to the 8th over 125 which reduces to 2X to the 8th over 5? I really don't understand this at all. \n" );
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Algebra.Com's Answer #51907 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( "Sort of a complex problem. What can be done for openers is to recall that when you raise \n" ); document.write( "a power to a power, you can just multiply the two exponents. So you can simplify the problem \n" ); document.write( "by multiplying the (-2/3) exponent times the (+12) exponent to get a new single exponent of (-8). \n" ); document.write( "The problem then becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Next, to get rid of the negative exponent you can put the term with a positive exponent as \n" ); document.write( "the denominator of a fraction whose numerator is 1. The problem then becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then by exponent rules the terms under the numerator can both be raised to the 8th power to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Next multiply the numerator and denominator of this fraction by \n" ); document.write( "The top \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This results in: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Notice the cancellation in the bottom: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "So at this point we are at: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "But by the rules of exponents the numerator can be expanded and the problem becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now, depending on how much further you want to go, you can divide \n" ); document.write( "and get (rounded off): \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "But maybe you could quit earlier than that or could use scientific notation to get \n" ); document.write( "an answer of \n" ); document.write( ". \n" ); document.write( "Hope this helps you understand exponents a little more. A lot of practice with various rules \n" ); document.write( "in doing this problem. \n" ); document.write( " |