document.write( "Question 72588: (125/8X to the 12 power ) all that raised to a -2/3 power. So 125 over 8X to the 12th power and all of that raised to the -2/3 power
\n" ); document.write( "I tried 125 to the -2/3 over 8 to the -2/3 (times) 8X to the -8 and got 125 over 8X to the -8.then fliped it because it is a negative exponent which would be 8X to the 8th over 125 which reduces to 2X to the 8th over 5? I really don't understand this at all.
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Algebra.Com's Answer #51907 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
\"%28%28125%2F%288%2AX%29%29%5E12%29%5E%28-2%2F3%29\"
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\n" ); document.write( "Sort of a complex problem. What can be done for openers is to recall that when you raise
\n" ); document.write( "a power to a power, you can just multiply the two exponents. So you can simplify the problem
\n" ); document.write( "by multiplying the (-2/3) exponent times the (+12) exponent to get a new single exponent of (-8).
\n" ); document.write( "The problem then becomes:
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\n" ); document.write( "\"%28%28125%2F%288%2AX%29%29%5E%28-8%29%29\"
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\n" ); document.write( "Next, to get rid of the negative exponent you can put the term with a positive exponent as
\n" ); document.write( "the denominator of a fraction whose numerator is 1. The problem then becomes:
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\n" ); document.write( "\"1%2F%28%28125%29%2F%288%2AX%29%29%5E8%29\"
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\n" ); document.write( "Then by exponent rules the terms under the numerator can both be raised to the 8th power to get:
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\n" ); document.write( "\"1%2F%28%28125%5E8%29%2F%28%288%2AX%29%5E8%29%29\"
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\n" ); document.write( "Next multiply the numerator and denominator of this fraction by \"%28%288%2AX%29%5E8%2F%288%2AX%29%5E8%29\".
\n" ); document.write( "The top
\n" ); document.write( "\"%288%2AX%29%5E8\" multiplies the \"1\" and the bottom \"%288%2AX%29%5E8\" multiplies the \"%28%28125%5E8%29%2F%28%288%2AX%29%5E8%29%29\".
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\n" ); document.write( "This results in:
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\n" ); document.write( "\"%288%2AX%29%5E8%2F%28%28%28125%5E8%29%2F%28%288%2AX%29%5E8%29%29%2A%288%2AX%29%5E8%29\"
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\n" ); document.write( "Notice the cancellation in the bottom:
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\n" ); document.write( "So at this point we are at:
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\n" ); document.write( "\"%288%2AX%29%5E8%2F%28125%29%5E8\"
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\n" ); document.write( "But by the rules of exponents the numerator can be expanded and the problem becomes:
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\n" ); document.write( "\"%288%5E8%29%2A%28X%5E8%29%2F%28125%5E8%29\"
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\n" ); document.write( "Now, depending on how much further you want to go, you can divide \"8%5E8\" by \"125%5E8\"
\n" ); document.write( "and get (rounded off):
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\n" ); document.write( "\"0.0000000003%2AX%5E8\".
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\n" ); document.write( "But maybe you could quit earlier than that or could use scientific notation to get
\n" ); document.write( "an answer of \"%282.814749767+%2A+10%5E%28-10%29%29%2AX%5E8\"
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\n" ); document.write( "Hope this helps you understand exponents a little more. A lot of practice with various rules
\n" ); document.write( "in doing this problem.
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