document.write( "Question 861353: Need help solving:\r
\n" );
document.write( "\n" );
document.write( "sin^2(x/2)-2 = 0 and\r
\n" );
document.write( "\n" );
document.write( "sec(x/2) = cos(x/2)\r
\n" );
document.write( "\n" );
document.write( "for exact solution over the interval [0,2pi].\r
\n" );
document.write( "\n" );
document.write( "Thx!
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #519034 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! sin^2(x/2)-2 = 0 \n" ); document.write( "sin^2(x/2) = 2 \n" ); document.write( "Ans: no solution since sin^2 cannot exceed +1. \n" ); document.write( "-----------------------------------\r \n" ); document.write( "\n" ); document.write( "sec(x/2) = cos(x/2) \n" ); document.write( "1/cos(x/2) = cos(x/2) \n" ); document.write( "cos^2(x/2) = 1 \n" ); document.write( "x/2 = 0 or x/2 = 2pi \n" ); document.write( "x = 0 or x = 4pi \n" ); document.write( "------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------------- \n" ); document.write( " |