document.write( "Question 861353: Need help solving:\r
\n" ); document.write( "\n" ); document.write( "sin^2(x/2)-2 = 0 and\r
\n" ); document.write( "\n" ); document.write( "sec(x/2) = cos(x/2)\r
\n" ); document.write( "\n" ); document.write( "for exact solution over the interval [0,2pi].\r
\n" ); document.write( "\n" ); document.write( "Thx!
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Algebra.Com's Answer #519034 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
sin^2(x/2)-2 = 0
\n" ); document.write( "sin^2(x/2) = 2
\n" ); document.write( "Ans: no solution since sin^2 cannot exceed +1.
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\n" ); document.write( "\n" ); document.write( "sec(x/2) = cos(x/2)
\n" ); document.write( "1/cos(x/2) = cos(x/2)
\n" ); document.write( "cos^2(x/2) = 1
\n" ); document.write( "x/2 = 0 or x/2 = 2pi
\n" ); document.write( "x = 0 or x = 4pi
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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