document.write( "Question 861427: write an equation in standard form of the line that passes through the point P(6,-1) and is perpendicular to the line described by the equation -2x + 3y = -6 \n" ); document.write( "
Algebra.Com's Answer #519023 by josgarithmetic(39618)\"\" \"About 
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This is how standard form equation for a line works:\r
\n" ); document.write( "\n" ); document.write( "\"ax%2Bby=c\", standard form.
\n" ); document.write( "Solve for y.
\n" ); document.write( "\"by=-ax%2Bc\"
\n" ); document.write( "\"y=-%28a%2Fb%29x%2Bc%2Fb\", slope-intercept form.\r
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\n" ); document.write( "\n" ); document.write( "The slope is \"-%28a%2Fb%29\" and the y-intercept is \"c%2Fb\".\r
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\n" ); document.write( "\n" ); document.write( "What you should know about perpendicular lines:\r
\n" ); document.write( "\n" ); document.write( "If two lines are perpendicular and their slopes are \"m%5B1%5D\" and \"m%5B2%5D\", then \"m%5B1%5D%2Am%5B2%5D=-1\".\r
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\n" ); document.write( "\n" ); document.write( "Returning to you given equation and to find line perpendicular containing P(6,-1):\r
\n" ); document.write( "\n" ); document.write( "The line perpendicular to the given \"-2x%2B3y=-6\" is \"highlight_green%283x%2B2y=c%29\", and knowing that this new line must contain the point (6,-1), use those coordinates to compute c.
\n" ); document.write( "\"highlight_green%28c=3%2A6%2B2%28-1%29%29\".
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