document.write( "Question 72487: (x-1)^2 + (y-8)^2 = 16
\n" ); document.write( "I've tried giving x a value and solving for y. Here is what I tried...
\n" ); document.write( "(1-1)^2 + (y-8)^2 = 16
\n" ); document.write( "0 + (y-8)^2 = 16
\n" ); document.write( "(y-8)(y-8) = 16
\n" ); document.write( "y^2 -8y -8y =64 = 16
\n" ); document.write( "y^2 - 16y + 64 = 16
\n" ); document.write( "y^2 - 8(y-y+8) = 16
\n" ); document.write( "y^2 + 8 =2
\n" ); document.write( "y^2 = 16
\n" ); document.write( "y = 4
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Algebra.Com's Answer #51901 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
\"%28x-1%29%5E2+%2B+%28y-8%29%5E2+=+16\"
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\n" ); document.write( "Here's a point to the right direction. Look in your textbook for the standard form of the
\n" ); document.write( "equation of a circle.
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\n" ); document.write( "The above problem is a circle whose center is found by getting its x and y values through solving
\n" ); document.write( "the two equations x-1 = 0 and y - 8 = 0.
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\n" ); document.write( "The radius of the circle is the square root of the right side.
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\n" ); document.write( "In summary, the graph of this equation is a circle whose center is located located at (1,8) and
\n" ); document.write( "whose radius is 4.
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\n" ); document.write( "Hope this points you in a little better direction. If you study how the equation for
\n" ); document.write( "a circle is derived you will get a little better idea of how the above form comes about.
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\n" ); document.write( "And don't feel too badly about this. The only reason I saw the answer immediately
\n" ); document.write( "was because the equation was written in a form that I recognized from a long time ago.
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