document.write( "Question 72487: (x-1)^2 + (y-8)^2 = 16
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document.write( "I've tried giving x a value and solving for y. Here is what I tried...
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document.write( "(1-1)^2 + (y-8)^2 = 16
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document.write( "0 + (y-8)^2 = 16
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document.write( "(y-8)(y-8) = 16
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document.write( "y^2 -8y -8y =64 = 16
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document.write( "y^2 - 16y + 64 = 16
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document.write( "y^2 - 8(y-y+8) = 16
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document.write( "y^2 + 8 =2
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document.write( "y^2 = 16
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document.write( "y = 4 \n" );
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Algebra.Com's Answer #51901 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( "Here's a point to the right direction. Look in your textbook for the standard form of the \n" ); document.write( "equation of a circle. \n" ); document.write( ". \n" ); document.write( "The above problem is a circle whose center is found by getting its x and y values through solving \n" ); document.write( "the two equations x-1 = 0 and y - 8 = 0. \n" ); document.write( ". \n" ); document.write( "The radius of the circle is the square root of the right side. \n" ); document.write( ". \n" ); document.write( "In summary, the graph of this equation is a circle whose center is located located at (1,8) and \n" ); document.write( "whose radius is 4. \n" ); document.write( ". \n" ); document.write( "Hope this points you in a little better direction. If you study how the equation for \n" ); document.write( "a circle is derived you will get a little better idea of how the above form comes about. \n" ); document.write( ". \n" ); document.write( "And don't feel too badly about this. The only reason I saw the answer immediately \n" ); document.write( "was because the equation was written in a form that I recognized from a long time ago. \n" ); document.write( " \n" ); document.write( " |