document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=861399>Question 861399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 36m. If the width were doubled and the length were increased by 11m, the perimeter would be 68m. What are the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #519002 by </B><A HREF=/tutors/aboutme.mpl?userid=ben720><B>ben720(159)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ben720><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=519002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is 36m. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2l%2B2w=36 ALIGN=MIDDLE  ALT=\"2l%2B2w=36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "If the width were doubled and length increased by 8, p=68 <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28l%2B11%29%2B2%2A2w=68 ALIGN=MIDDLE  ALT=\"2%28l%2B11%29%2B2%2A2w=68\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2l%2B22%2B4w=68 ALIGN=MIDDLE  ALT=\"2l%2B22%2B4w=68\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2l%2B4w=46 ALIGN=MIDDLE  ALT=\"2l%2B4w=46\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<TABLE  BORDER=1>\n" );
document.write( "\n" );
document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=linear_substitution.solver>SOLVE linear system by SUBSTITUTION</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>Solve:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++2%5Cx+%2B+2%5Cy+=+36%2C%0D%0A++++2%5Cx+%2B+4%5Cy+=+46+%29%0D%0A++ ALIGN=MIDDLE  ALT=\"+system%28+%0D%0A++++2%5Cx+%2B+2%5Cy+=+36%2C%0D%0A++++2%5Cx+%2B+4%5Cy+=+46+%29%0D%0A++\"   DISABLED_style= \"max-width:90%; height:auto;\" >We'll use substitution. After moving 2*y to the right, we get:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Ax+=+36+-+2%2Ay ALIGN=MIDDLE  ALT=\"2%2Ax+=+36+-+2%2Ay\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+36%2F2+-+2%2Ay%2F2 ALIGN=MIDDLE  ALT=\"x+=+36%2F2+-+2%2Ay%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Substitute that<BR>\n" );
document.write( "  into another equation:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A%2836%2F2+-+2%2Ay%2F2%29+%2B+4%5Cy+=+46 ALIGN=MIDDLE  ALT=\"2%2A%2836%2F2+-+2%2Ay%2F2%29+%2B+4%5Cy+=+46\"   DISABLED_style= \"max-width:90%; height:auto;\" > and simplify: So, we know that y=5. Since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+36%2F2+-+2%2Ay%2F2 ALIGN=MIDDLE  ALT=\"x+=+36%2F2+-+2%2Ay%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, x=13.<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  Answer: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28+x=13%2C+y=5+%29 ALIGN=MIDDLE  ALT=\"system%28+x=13%2C+y=5+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "  </TD></TR>\n" );
document.write( "</TABLE>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );