document.write( "Question 861360: When (67th + 67) is divided by 68, the remainder is:
\n" ); document.write( "a) 1 b) 63 c) 66 d) 67.
\n" ); document.write( "The answer is 66. But I dont know how it comes. Please elaborate it. \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #518987 by ben720(159) $\"\"$ $\"About$

You can put this solution on YOUR website!
The remainder is whatever the 68 doesn't cover. Because 67 is less than 68, 2 67s is less than 2 68s. Therefore, only one 68 will fit into 67+67. In algebraic form:
\n" ); document.write( " $\"67%2B67=68%2Bx\"$
\n" ); document.write( "Because 67 is only one less than 68, when you subtract 68 from both sides, it becomes 67-1, or 66. \r
\n" ); document.write( "\n" ); document.write( "In non-algebraic form:
\n" ); document.write( "The answer is $\"67%2B67-68\"$
\n" ); document.write( " $\"67-1\"$
\n" ); document.write( " $\"66\"$
\n" ); document.write( " \n" ); document.write( "

\n" );