document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=861325>Question 861325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor to find the center and radius of the given equation: <BR>\n" );
document.write( "a) x^2+y^2-8x=65<BR>\n" );
document.write( "I understood how to solve this question and it came out to (x+4)^2+y^2=81<BR>\n" );
document.write( "r=9 and (h.k)=(4,0)<BR>\n" );
document.write( "My question is how to solve this next one.<BR>\n" );
document.write( "b) x^2+y^2-4x+14y=-17<BR>\n" );
document.write( "I don't understand why there is a \"14y\" and what I am suppose to do with it.<BR>\n" );
document.write( "I first began by subtracting 10 from \"14y\" and \"-17\" and it came out to<BR>\n" );
document.write( "(x+2)^2+(y-2)^2=-27. I don't believe it is correct though because I cannot square -27 to get the radius. Should I add 50 to both sides instead to receive 47 as the radius? So confused... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #518946 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=518946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+y^2-4x+14y=-17\r<BR>\n" );
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document.write( "x^2-4x+y^2+14y=-17<BR>\n" );
document.write( "complete the square for x and for y\r<BR>\n" );
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document.write( "x^2-4x+4+y^2+14y+49=-17+4+49<BR>\n" );
document.write( "(x-2)^2+(y+7)^2=36 \r<BR>\n" );
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