document.write( "Question 861182: Pls do help in solving my problem:
\n" ); document.write( "Two parallel chords of length 10cm and 14cm lie on the same side of a circle of radius 24cm find the distance between the chords
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Algebra.Com's Answer #518944 by KMST(5328)\"\" \"About 
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Half of the longer chord measures \"14cm%2F2=7cm\".
\n" ); document.write( "Half of the shorter chord measures \"10cm%2F25cm\".
\n" ); document.write( "Drawing, not to scale:
\n" ); document.write( " The perpendicular bisector of a chord goes through the center of the circle.
\n" ); document.write( "Along with one half of the chord and the radius to one of the chord's ends, it forms a right triangle.
\n" ); document.write( "With the two chords, we have two right triangles.
\n" ); document.write( "In each of those triangles the hypotenuse measures 24 cm.
\n" ); document.write( "The legs of one of those triangles measure \"x\"cm and \"7\" cm,
\n" ); document.write( "so \"x%5E2%2B7%5E2=24%5E2\" --> \"x%5E2%2B49=576\" --> \"x%5E2=576-49\" --> \"x%5E2=527\" --> \"x=sqrt%28527%29=about22.96\"
\n" ); document.write( "The legs of the other triangle measure \"y\"cm and \"5\" cm,
\n" ); document.write( "so \"x%5E2%2B5%5E2=24%5E2\" --> \"x%5E2%2B25=576\" --> \"x%5E2=576-25\" --> \"x%5E2=551\" --> \"x=sqrt%28551%29=about23.47\"
\n" ); document.write( "The distance between the chords is
\n" ); document.write( "\"sqrt%28551%29-sqrt%28527%29\"= approx.\"23.47cm-22.96cm\"= approx.\"0.51cm\"
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