document.write( "Question 861305: Solve the equation
\n" ); document.write( "tan θ = − square of 3 / 3
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Algebra.Com's Answer #518940 by stanbon(75887)\"\" \"About 
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tan θ = − square of 3 / 3
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\n" ); document.write( "tan(t) = -1/sqrt(3)
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\n" ); document.write( "Reference angle: pi/6
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\n" ); document.write( "Since tan is negative: t = (5/6)pi or (11/6)pi
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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