document.write( "Question 861248: Find tan(s+t) if cos s = (-1/5), sin t = 3/5, and s and t are in quadrant 2.
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document.write( "I have ready substituted values into the tan sum identity, but I'm having trouble with the arithmetic. \n" );
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Algebra.Com's Answer #518929 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find tan(s+t) if cos s = (-1/5), sin t = 3/5, and s and t are in quadrant 2. \n" ); document.write( "*** \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "cos(s)=-1/5 \n" ); document.write( " \n" ); document.write( "tan(s)=sin/cos=-√24/1=-√24 \n" ); document.write( "... \n" ); document.write( "sin(t)=3/5 (working with a (3-4-5) reference right triangle in quadrant 2) \n" ); document.write( "cos(t)=-4/5 \n" ); document.write( "tan(t)=sin/cos=-3/4 \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "tan(s+t)=(-√24-3/4)/(1-√24*(3/4) \n" ); document.write( "... \n" ); document.write( "calculator check: \n" ); document.write( "cos(s)=-1/5 \n" ); document.write( "s≈101.54 deg \n" ); document.write( "sin(t)=3/5 \n" ); document.write( "t≈143.13 \n" ); document.write( "s+t≈244.67 \n" ); document.write( "tan(s+t)=tan(244.67)≈2.112… \n" ); document.write( "exact value as calculated=(-√24-3/4)/(1-√24*(3/4)≈2.112... \n" ); document.write( "note: let me know if my solution is correct, helpful and understandable\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |