document.write( "Question 861121: Write logsub7(1/49)=-2 in exponential form. \n" ); document.write( "

Algebra.Com's Answer #518849 by stanbon(75887) $\"\"$ $\"About$

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Write logsub7(1/49)=-2 in exponential form
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\n" ); document.write( "base = 7
\n" ); document.write( "log = exponent = -2
\n" ); document.write( "result = 1/49
\n" ); document.write( "----
\n" ); document.write( "7^-2 = 1/49
\n" ); document.write( "---------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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