document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=861069>Question 861069</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Side b of a triangle is twice as long as side c. Side a is three meters longer than side b. The perimeter is forty-eight meters long. Find the length of each side.\r<BR>\n" );
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document.write( "How do I set up the equations to solve? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #518827 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39627)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=518827\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a, b, c, the side lengths of the triangle.<BR>\n" );
document.write( "Translate the description:<BR>\n" );
document.write( "b=2c;<BR>\n" );
document.write( "a=3+b;<BR>\n" );
document.write( "a+b+c=48.\r<BR>\n" );
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document.write( "Notice the first two equations both use b.  Suggestion is solve c in terms of b and solve a in terms of b (that one already given), and substitute into the perimeter equation.  Now you can solve for the value of b.  Solve then for the other two sides. </SPAN>\n" );
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