document.write( "Question 861053: log_3(x+6)+log_3(x-6)-log_3x=2 \n" ); document.write( "
Algebra.Com's Answer #518804 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi,
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document.write( "\"log%283%2C%28x%2B6%29%28x-6%29%2Fx%29+=+2\"
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document.write( "    \"%28x%2B6%29%28x-6%29%2Fx++=+9\"
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document.write( "        x^2 - 36 = 9x
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document.write( "        x^2 - 9x - 36 = 0
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document.write( "         (x +4)(x-12) = 0     |Tossing out negative x as an extraneous root
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document.write( "                 x = 12 \n" );
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