document.write( "Question 860964: a cyclist traveled 60 mi at a constant rate before reducing the speed by 7mph. Another 40 mi was traveled at the reduced speed. The total time for the 100-mile trip was 9 h. Find the rate during the first 60 mi. \n" ); document.write( "
Algebra.Com's Answer #518770 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
a cyclist traveled 60 mi at a constant rate before reducing the speed by 7mph. Another 40 mi was traveled at the reduced speed. The total time for the 100-mile trip was 9 h. Find the rate during the first 60 mi.
\n" ); document.write( "-----
\n" ); document.write( "Original leg DATA:
\n" ); document.write( "dist = 60 miles ; rate = x mph; time = 60/x hrs
\n" ); document.write( "----------------------
\n" ); document.write( "2nd leg DATA:
\n" ); document.write( "distance = 40 miles ; rate = x-7 mph ; time = 40/(x-7) hrs
\n" ); document.write( "-------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "time + time = 9 hrs
\n" ); document.write( "-----
\n" ); document.write( "60/x + 40/(x-7) = 9
\n" ); document.write( "60(x-7) + 40x = 9x(x-7)
\n" ); document.write( "------
\n" ); document.write( "100x - 420 = 9x^2 - 63x
\n" ); document.write( "-----
\n" ); document.write( "9x^2 - 163x + 420 = 0
\n" ); document.write( "x = 15 mph
\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "----------------------- \n" ); document.write( "
\n" );