document.write( "Question 860960: Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 12 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with σ = 0.20 gram.
\n" ); document.write( " (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. (Round your answers to two decimal places.) \r
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\n" ); document.write( "\n" ); document.write( "A.lower limit \r
\n" ); document.write( "\n" ); document.write( "B.upper limit \r
\n" ); document.write( "\n" ); document.write( "c. margin of error
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Algebra.Com's Answer #518739 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "ME = \"1.2816%28.20%2Fsqrt%2812%29%29\"= .07 (2 decimal points
\n" ); document.write( "CI: μ-ME < u < μ + ME
\n" ); document.write( "CI: 3.15g-ME < u < 3.15g + ME
\n" ); document.write( "CI: 3.08g < u < 3.22g
\n" ); document.write( "CI z -value
\n" ); document.write( "80% z= 1.2816
\n" ); document.write( "90% z =1.645
\n" ); document.write( "92% z = 1.751
\n" ); document.write( "95% z = 1.96
\n" ); document.write( "98% z = 2.326
\n" ); document.write( "99% z = 2.576
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