document.write( "Question 860931: Erin starts riding her bike. She is travelling at 10km/h. An hour after Erin starts, her sister, Makayla starts riding her bike. She is travelling at 16km/h. After how long (time) will Makayla catch up to her sister? \n" ); document.write( "
Algebra.Com's Answer #518717 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the time taken by Erin when her sister meets her be t\r \n" ); document.write( "\n" ); document.write( "Makayla will take t-1\r \n" ); document.write( "\n" ); document.write( "distans traveled by both is same \n" ); document.write( "d=rt\r \n" ); document.write( "\n" ); document.write( "12t = 16(t-1)\r \n" ); document.write( "\n" ); document.write( "12t=16t-16\r \n" ); document.write( "\n" ); document.write( "4t=16 \n" ); document.write( "t=4\r \n" ); document.write( "\n" ); document.write( "catchup time = 4 hours\r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |