document.write( "Question 860930: Erin starts riding her bike. She is travelling at 10km/h. An hour after Erin starts, her sister, Makayla starts riding her bike. She is travelling at 16km/h. After how long (time) will Makayla catch up to her sister? \n" ); document.write( "
Algebra.Com's Answer #518715 by mananth(16946)\"\" \"About 
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Erin 10 km/h
\n" ); document.write( "Makyala 16 km/h
\n" ); document.write( "Difference in time= 1.00 hour
\n" ); document.write( "Erin will have covered 10.00 km when Makyala starts
\n" ); document.write( "catch up distance= 10.00 km
\n" ); document.write( "catch up speed = 16 -10
\n" ); document.write( "catch up speed = 6 km/h
\n" ); document.write( "Catchup time = catchup distance/catch up speed
\n" ); document.write( "catch up time= 10/6 = 5/3 hours
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