document.write( "Question 860825: a ball is thrown vertically upward with an initial speed of 48 ft/s. its height, in feet, after t seconds is given by h=48t-16t^2. how high does the ball go? \n" ); document.write( "

Algebra.Com's Answer #518644 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "h = -16t^2 + 48t
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document.write( "h = -16(t-3/2)^2 + 16(9/4)
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document.write( "h = -16(t-3/2)^2 + 36
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document.write( " 36ft is how high the ball goes (reaches that height after 1.5 sec) \n" );
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