document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=860704>Question 860704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve -2(x - 3a) = -3 + a(2a - 3b) for x  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #518629 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=518629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  -2(x - 3a) = -3 + a(2a - 3b)<BR>\n" );
document.write( "-2X+6A=-3+2A^2-3AB<BR>\n" );
document.write( "-2X=-3+2A^2-3AB-6A<BR>\n" );
document.write( "-2X=2A^2-3AB-6A-3<BR>\n" );
document.write( "-2X=A(2A-3B-6)-3<BR>\n" );
document.write( "X=[A(2A-3B-6)-3]/-2 <BR>\n" );
document.write( "X=-[A(2A-3B-6)-3]/2 ANS </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );