document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=860567>Question 860567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jeff leaves his house on his bicycle at 7:30am and averages 5 miles per hour. His wife, Joan, leaves at 8:00am, following the same path and averaging 8 miles per hour. At what time will Joan catch up with Jeff? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #518521 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=518521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here speeds are different and time too\r<BR>\n" );
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document.write( "but distance traveled by both is same\r<BR>\n" );
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document.write( "let jeff take t hours to reach the point of catchup\r<BR>\n" );
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document.write( "his distance is 5t\r<BR>\n" );
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document.write( "His wife leaves 1/2 hour later. so she takes (t-1/2) hour\r<BR>\n" );
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document.write( "d= 8 * (t-1/2)\r<BR>\n" );
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document.write( "8(t-1/2) = 5t\r<BR>\n" );
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document.write( "8(2t-1)/2=5t\r<BR>\n" );
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document.write( "4(2t-1)=5t\r<BR>\n" );
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document.write( "10t-4=5t\r<BR>\n" );
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document.write( "10t-5t=4\r<BR>\n" );
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document.write( "5t=4\r<BR>\n" );
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document.write( "t=4/5 hours\r<BR>\n" );
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document.write( "4/5 * 5 = 4 miles\r<BR>\n" );
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document.write( "Joan rate =8 mph<BR>\n" );
document.write( "d=4\r<BR>\n" );
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document.write( "Joan time = 1/2 hour\r<BR>\n" );
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document.write( "she will catch up at 8.00 am\r<BR>\n" );
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document.write( " </SPAN>\n" );
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