document.write( "Question 860573: In 12 years, a man will be three times as old as his son; the difference of their present ages is 30, find their present ages \n" ); document.write( "
Algebra.Com's Answer #518514 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! In 12 years, a man will be three times as old as his son; the difference of their present ages is 30, find their present ages \n" ); document.write( "*** \n" ); document.write( "at present: \n" ); document.write( "let x=son's age \n" ); document.write( "30+x=father's age \n" ); document.write( "... \n" ); document.write( "12 years hence: \n" ); document.write( "x+12=son's age \n" ); document.write( "30+x+12=42+x=father's age \n" ); document.write( "... \n" ); document.write( "42+x=3(x+12) \n" ); document.write( "42+x=3x+36 \n" ); document.write( "2x=6 \n" ); document.write( "x=3 \n" ); document.write( "30+x=33 \n" ); document.write( "... \n" ); document.write( "son's present age=3 \n" ); document.write( "father's present age=33 \n" ); document.write( " |