document.write( "Question 860573: In 12 years, a man will be three times as old as his son; the difference of their present ages is 30, find their present ages \n" ); document.write( "
Algebra.Com's Answer #518514 by lwsshak3(11628)\"\" \"About 
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In 12 years, a man will be three times as old as his son; the difference of their present ages is 30, find their present ages
\n" ); document.write( "***
\n" ); document.write( "at present:
\n" ); document.write( "let x=son's age
\n" ); document.write( "30+x=father's age
\n" ); document.write( "...
\n" ); document.write( "12 years hence:
\n" ); document.write( "x+12=son's age
\n" ); document.write( "30+x+12=42+x=father's age
\n" ); document.write( "...
\n" ); document.write( "42+x=3(x+12)
\n" ); document.write( "42+x=3x+36
\n" ); document.write( "2x=6
\n" ); document.write( "x=3
\n" ); document.write( "30+x=33
\n" ); document.write( "...
\n" ); document.write( "son's present age=3
\n" ); document.write( "father's present age=33
\n" ); document.write( "
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