document.write( "Question 860366: a used car salesman in a small town states that on average, it takes 5 days to sell a car. assume that the probability distribution of the length of the time between sales is exponentially distributed \r
\n" ); document.write( "\n" ); document.write( "what is the probability that he will have to wait between 6 and 10 days before making another sale?
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Algebra.Com's Answer #518367 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Poisson distribution
\n" ); document.write( "average: 5 days
\n" ); document.write( "TI syntax P(# ≤ x)= poissioncdf(mean, largest x-value).
\n" ); document.write( "P(6 ≤ x ≤ 10) = poissioncdf(5, 10) - poissioncdf(5, 6) = .9863 -.7622
\n" ); document.write( "0r if You mean
\n" ); document.write( "P(6 < x < 10) = poissioncdf(5, 9) - poissioncdf(5, 7) \n" ); document.write( "
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