document.write( "Question 860367: a researcher conducted a survey on a university campus for a sample of 64 seniors and reported that, seniors on average read 32 books in the prior academic semester, with a standard deviation of 21 books. assume that distribution is normal.\r
\n" ); document.write( "\n" ); document.write( "a)calculate the probability that the sample mean is above 34 books \r
\n" ); document.write( "\n" ); document.write( "b)determine the probability that the sample mean is between 31 and 33 books\r
\n" ); document.write( "\n" ); document.write( "c)determine the probability that the sample mean will be below 29 books \n" ); document.write( "
Algebra.Com's Answer #518364 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi,
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document.write( "m = 32, SD = 21, s = 21/sqrt(64) = 2.625
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document.write( "TI syntax is normalcdf(smaller, larger, µ, σ)
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document.write( "P(x > 34) = normalcdf(34, 100, 32, 2.625)    |100 a placeholder for VERY large
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document.write( "P(31 ≤ x ≤ 33)= normalcdf(31, 33, 32, 2.625)
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document.write( "P(x < 29) = normalcdf(-100, 29, 32, 2.625) \n" );
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