document.write( "Question 860368: in an inspection of 4000 electrical components built to a very high specification, 10 were found to be defective.\r
\n" ); document.write( "\n" ); document.write( "determine the 90% confidence interval limit of the true population of defectives in the population of the components
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Algebra.Com's Answer #518356 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "CI z-value
\n" ); document.write( "90% z =1.645
\n" ); document.write( "92% z = 1.751
\n" ); document.write( "95% z = 1.96
\n" ); document.write( "98% z = 2.326
\n" ); document.write( "99% z = 2.576
\n" ); document.write( "p = 10/4000 = .0025, q = .0075
\n" ); document.write( "ME = 1.645\"sqrt%28%28.0025%2A.0075%29%2F4000%29\"
\n" ); document.write( "CI: 10-ME < u < 10 + ME \n" ); document.write( "
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