document.write( "Question 860283: Let a triangle of sides 3,4,5 be such that the longest side is the base. Then the height is :
\n" ); document.write( "A 15/4
\n" ); document.write( "B 20/3
\n" ); document.write( "C 16/5
\n" ); document.write( "D 12/5
\n" ); document.write( "E 9/4
\n" ); document.write( "

Algebra.Com's Answer #518291 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Let a triangle of sides 3,4,5 be such that the longest side is the base. Then the height is :
\n" ); document.write( "A 15/4
\n" ); document.write( "B 20/3
\n" ); document.write( "C 16/5
\n" ); document.write( "D 12/5
\n" ); document.write( "E 9/4
\n" ); document.write( "------------
\n" ); document.write( "The easy way:
\n" ); document.write( "Using 4 as the base and 3 as the height, area = b*h/2 = 6
\n" ); document.write( "----
\n" ); document.write( "With 5 as the base:
\n" ); document.write( "Area = 5*h/2 = 6
\n" ); document.write( "h = 12/5
\n" ); document.write( "
\n" ); document.write( "
\n" );