document.write( "Question 860213: AN Astronaut standing on the surface of the moon throws a rock into the air with and initial velocity of 27 feet per second. the astronaut hand is 6 feet above the surface of the moo. The height of the rock is given by h= -2.7f2+27t+6.
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document.write( "How many seconds was the rock in the air? \n" );
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Algebra.Com's Answer #518281 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! AN Astronaut standing on the surface of the moon throws a rock into the air with and initial velocity of 27 feet per second. \n" ); document.write( " the astronaut hand is 6 feet above the surface of the moon. \n" ); document.write( " The height of the rock is given by h= -2.7f2+27t+6. \n" ); document.write( "How many seconds was the rock in the air? \n" ); document.write( ": \n" ); document.write( "When the rock strikes the ground, h=0 \n" ); document.write( "-2.7t^2 + 27t + 6 = 0 \n" ); document.write( "Use the quadratic formula to find t, \n" ); document.write( " \n" ); document.write( " where a=-2.7, b=27, c=6 \n" ); document.write( "t = \n" ); document.write( "do the math, I got a positive solution of t=10.275 sec, see what you get. \n" ); document.write( " |