document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=860084>Question 860084</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with the following\r<BR>\n" );
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document.write( "Given that 2y = 16x – 3 and 3y+2 = 27x, find the value of x + y\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #518199 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=518199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that 2y = 16x – 3 and 3y+2 = 27x, find the value of x + y <BR>\n" );
document.write( "solve first equation for y<BR>\n" );
document.write( "y = 8x - 3/2<BR>\n" );
document.write( "substitute for y in second equation<BR>\n" );
document.write( "3(8x - 3/2) + 2 = 27x<BR>\n" );
document.write( "24x - 9/2 + 2 = 27x<BR>\n" );
document.write( "3x = -5/2<BR>\n" );
document.write( "x = -5/6<BR>\n" );
document.write( "substitute for x in first equation<BR>\n" );
document.write( "2y = 16(-5/6) -3<BR>\n" );
document.write( "2y = -80/6 - 18/6<BR>\n" );
document.write( "2y = -98/6<BR>\n" );
document.write( "y = -49/6<BR>\n" );
document.write( "x + y = -5/6 -49/6 = - 54/6 = -9\r<BR>\n" );
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