document.write( "Question 860161: the width of a rectangle is 5cm greater than its length. if the area of the reactangle is 124cm^2, what are the approximate dimensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #518180 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Let x represent the length.  The width is (x+5)
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document.write( "x(x+5) = 124cm^2
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document.write( "x^2  + 5x = 124
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document.write( "x^2 + 5x - 124 = 0
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document.write( " x = `8.9, the length.  The width ` 13.9
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document.write( "Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation  (in our case ) has the following solutons:
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document.write( "  For these solutions to exist, the discriminant  should not be a negative number.
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document.write( "  First, we need to compute the discriminant : .
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document.write( "  
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document.write( "  Discriminant d=521 is greater than zero. That means that there are two solutions: .
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document.write( "    Quadratic expression  can be factored:
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document.write( "  Again, the answer is: 8.91271221051333, -13.9127122105133.\n" );
document.write( "Here's your graph:
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