document.write( "Question 860162: (12x-4)(3x+6)=0 \n" ); document.write( "
Algebra.Com's Answer #518169 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "(12x-4)(3x+6)=0
\n" ); document.write( "(12x-4)=0, x = 4/12 = 1/3
\n" ); document.write( "(3x+6)=0, x = -6/3 = -2
\n" ); document.write( "roots: -2, 1/3
\n" ); document.write( "(12x-4)(3x+6)=0 = 36x^2 + 60x - 24 = 12(3x^2 + 5x - 2)
\n" ); document.write( "F First terms
\n" ); document.write( "O Outside terms 72x
\n" ); document.write( "I Inside terms -12x
\n" ); document.write( "L Last terms
\n" ); document.write( " \n" ); document.write( "
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