document.write( "Question 859829: Each side of the right triangle ABC is tangent to the circle with center o. The radius of the circle is 4 inches and the length AC is 12 inches. Find each of the following. \r
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document.write( "m∠C (Angle C)
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document.write( "m∠B (Angle B)
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document.write( "Line BC\r
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Algebra.Com's Answer #518142 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! Each side of the right triangle ABC is tangent to the circle with center O. The radius of the circle is 4 inches and the length AC is 12 inches. Find each of the following. \n" ); document.write( "m∠C (Angle C) \n" ); document.write( "m∠B (Angle B) \n" ); document.write( "Line BC \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Draw radii (in green) to the three points of tangency, \n" ); document.write( "OD, OE, and OF, which are perpendicular to the three \n" ); document.write( "sides. Draw OC and OB. Extend FO till it intersects BC at G. \n" ); document.write( "Then draw GH⊥AB \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OD=4, so AF=4, and since AC=12, FC=8 \n" ); document.write( " \n" ); document.write( "∠FCO = ∠ECG because the center of inscribed circle O \n" ); document.write( "is the intersection of the angle bisectors. \n" ); document.write( " \n" ); document.write( "ΔCFO = ΔCEO hypotenuse and a side equal \n" ); document.write( " \n" ); document.write( "∠FOC ≅ ∠EOC \n" ); document.write( " \n" ); document.write( "∠FOE = 2∠FOC, CF = CE = 8 \n" ); document.write( " \n" ); document.write( "tan(∠FOC) = \n" ); document.write( " \n" ); document.write( "CE = CF = 8 \n" ); document.write( " \n" ); document.write( "tan(∠FOE) = tan(∠FOC) = \n" ); document.write( " \n" ); document.write( "∠GOE = 180°-∠FOE \n" ); document.write( " \n" ); document.write( "tan(∠GOE) = 180°-∠FOE \n" ); document.write( " \n" ); document.write( "tan(∠GOE) = tan(180°-∠FOE) = -tan(∠FOE) = \n" ); document.write( " \n" ); document.write( "tan(∠GOE) = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "EG = \n" ); document.write( "\n" ); document.write( "OG = \n" ); document.write( " \n" ); document.write( "ΔOEG ≅ ΔGHB because DE=GH=4 and ∠GBH = ∠OGE \n" ); document.write( " parallel lines FG,AB cut by \n" ); document.write( " transversal BC \n" ); document.write( " \n" ); document.write( "GB = OG = \n" ); document.write( " \n" ); document.write( "BC = CE + EG + GB = 8 + \n" ); document.write( "\n" ); document.write( "∠C = ∠ACB = cos-1 \n" ); document.write( " \n" ); document.write( "∠B = ∠ABC = sin-1 \n" ); document.write( "\n" ); document.write( "Edwin \n" ); document.write( " |