document.write( "Question 72485This question is from textbook Intermediate Algebra
\n" ); document.write( ": Find the equation in standard form, with all interger coefficients, of the line perpendicular to x - 5y = 4 and passing through (-3,5). \n" ); document.write( "
Algebra.Com's Answer #51814 by stanbon(75887)\"\" \"About 
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Find the equation in standard form, with ll interger coefficients, of the line perpendicular to x - 5y = 4 and passing through (-3,5).
\n" ); document.write( "The given line may be written as y=(1/5)x-(4/5), so it has a slope of 1/5.
\n" ); document.write( "A perpendicular line must have a slope of -5.
\n" ); document.write( "The equation you want is y=mx+b where y=5 when x=-3, and m=-5
\n" ); document.write( "Solve for \"b\".
\n" ); document.write( "5=(1/5)(-3)+b
\n" ); document.write( "b=25/15/3+3/5
\n" ); document.write( "b=28/5
\n" ); document.write( "EQUATION:
\n" ); document.write( "y=-5x+28/5
\n" ); document.write( "Convert to standard form:
\n" ); document.write( "Multiply thru by 5 to get:
\n" ); document.write( "5y=-25x+28
\n" ); document.write( "Rearrange to get the form ax+by=c
\n" ); document.write( "25x+5y=28
\n" ); document.write( "==========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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