document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=860074>Question 860074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1+cscA=cscA(1+sinA) ~ How to prove that LS=RS </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #518114 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=518114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm only going to be altering the right side.\r<BR>\n" );
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document.write( "1+cscA=cscA(1+sinA)\r<BR>\n" );
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document.write( "1+cscA=cscA(1)+cscA(sinA) ... distribution\r<BR>\n" );
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document.write( "1+cscA=cscA(1)+1/sinA(sinA) ... Substitution (note: csc(A) = 1/sin(A))\r<BR>\n" );
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document.write( "1+cscA=cscA+sinA/sinA ... multiplication\r<BR>\n" );
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document.write( "1+cscA=cscA+1 ... division\r<BR>\n" );
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document.write( "1+cscA=1+cscA ... use the commutative property of addition\r<BR>\n" );
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document.write( "So the identity is confirmed. </SPAN>\n" );
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