document.write( "Question 860058: A = P 8500(1 + .09)-12
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document.write( "P = 8500(1.09)-12
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document.write( "P = 8500/(1.09)-12\r
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document.write( "I am trying to determine how much principal I need to invest today, to reach $8500 in 12years at 9% compounded interests. I can't seem to figure out the principal that I need - thank you! \r
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Algebra.Com's Answer #518113 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Principal P = x \n" ); document.write( "Amount= 8500 \n" ); document.write( "years=n 12 \n" ); document.write( "compounded 1 times a year \n" ); document.write( "Rate = 9.00 0.090 \n" ); document.write( "Amount = P*((n+r)/n)^n \n" ); document.write( " \n" ); document.write( "8500 = x *( 1 + r/n )^ n \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "8500 = P ( 1 + 0.090 / 1 ) ^ 1 * 12 \n" ); document.write( " \n" ); document.write( "8500 = P( 1.09000 )^ 12 \n" ); document.write( " \n" ); document.write( "8500 /( 1.09 )^ 12 = P \n" ); document.write( " \n" ); document.write( "P= $3022.05 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |