document.write( "Question 860058: A = P 8500(1 + .09)-12
\n" ); document.write( "P = 8500(1.09)-12
\n" ); document.write( "P = 8500/(1.09)-12\r
\n" ); document.write( "\n" ); document.write( "I am trying to determine how much principal I need to invest today, to reach $8500 in 12years at 9% compounded interests. I can't seem to figure out the principal that I need - thank you! \r
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Algebra.Com's Answer #518113 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Principal P = x
\n" ); document.write( "Amount= 8500
\n" ); document.write( "years=n 12
\n" ); document.write( "compounded 1 times a year
\n" ); document.write( "Rate = 9.00 0.090
\n" ); document.write( "Amount = P*((n+r)/n)^n
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\n" ); document.write( "8500 = x *( 1 + r/n )^ n
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\n" ); document.write( "8500 = P ( 1 + 0.090 / 1 ) ^ 1 * 12
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\n" ); document.write( "8500 = P( 1.09000 )^ 12
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\n" ); document.write( "8500 /( 1.09 )^ 12 = P
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\n" ); document.write( "P= $3022.05
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