document.write( "Question 859981: the velocity of a dropped object when it hits the ground can be found using v= the square root of 2gd where v is the velocity in feet per second g is the acceleration due to gravity and d is the distance in feet the object drops find the speed of a penny when it hits the ground after being dropped from 984 feet is 32 feet per second squared for g \n" ); document.write( "
Algebra.Com's Answer #518101 by stanbon(75887)\"\" \"About 
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the velocity of a dropped object when it hits the ground can be found using v= the square root of 2gd where v is the velocity in feet per second g is the acceleration due to gravity and d is the distance in feet the object drops find the speed of a penny when it hits the ground after being dropped from 984 feet is 32 feet per second squared for g
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\n" ); document.write( "v = the square root of 2gd
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\n" ); document.write( "v = sqrt(2gd)
\n" ); document.write( "Solve for \"g\"::
\n" ); document.write( "32 = sqrt(2*g*984)
\n" ); document.write( "1968g = 32^2
\n" ); document.write( "g = 0.5203 ft/sec^2 (acceleration due to gravity)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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