document.write( "Question 859938: About 4% of the scientists in the National Academy of Sciences believe in PSI (parapsychology such as psychokinesis, telepathy, and astral projection). At a convention 107 members show up. Let X be the number of scientists at the convention who believe in PSI. You may assume for the following questions that X is binomially distributed with parameters n=107 and p=0.04.\r
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document.write( "(a) How many scientists at the convention do you expect do believe in PSI? Answer\r
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document.write( "(b) What are the chances that none of the scientists at the convention believes in PSI? Answer\r
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document.write( "(c) What are the chances that at least 4 scientists at the convention believe in PSI? Answer\r
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document.write( "(d) What is the standard deviation of X \n" );
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Algebra.Com's Answer #518077 by stanbon(75887) ![]() You can put this solution on YOUR website! About 4% of the scientists in the National Academy of Sciences believe in PSI (parapsychology such as psychokinesis, telepathy, and astral projection). At a convention 107 members show up. Let X be the number of scientists at the convention who believe in PSI. You may assume for the following questions that X is binomially distributed with parameters n=107 and p=0.04. \n" ); document.write( "(a) How many scientists at the convention do you expect to believe in PSI? Answer:: np = 107*0.04 = 4.28 \n" ); document.write( "--------------------------------------- \n" ); document.write( "(b) What are the chances that none of the scientists at the convention believes in PSI? Answer P(x = 0) = 0.96^107 = 0.0127 \n" ); document.write( "--------------------------------------- \n" ); document.write( "(c) What are the chances that at least 4 scientists at the convention believe in PSI? Answer:: P(4<= x <=107) = 1-P(0<=x<=3) \n" ); document.write( "= 1-binomcdf(107,0.04,3) = 0.6240 \n" ); document.write( "---------------------------------------- \n" ); document.write( "(d) What is the standard deviation of X \n" ); document.write( "std = sqrt(npq) = sqrt(107*0.04*0.96) = 2.0270 \n" ); document.write( "================================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====================== \n" ); document.write( " |