document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=859855>Question 859855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (6y-4)/(3y+9) = 1/1\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #518048 by </B><A HREF=/tutors/aboutme.mpl?userid=Porsha+Solis><B>Porsha Solis(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Porsha+Solis><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Porsha+Solis><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=518048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (6y-4)/(3y+9)=1/1\r<BR>\n" );
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document.write( "The simplified form to this equation is:\r<BR>\n" );
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document.write( "(3y-13)/(3y+9)=0\r<BR>\n" );
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document.write( "The solution is:\r<BR>\n" );
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document.write( "y=13/3 </SPAN>\n" );
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