document.write( "Question 859709: Hello, I have been working on this statistics question for a while now. I keep coming up with. 125 (after rounding 3 places), so I am missing something and I am not too sure where. Any help is greatly appreciated.\r
\n" ); document.write( "\n" ); document.write( "Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all visitors to the website are looking for other websites. Assuming that this estimate is correct, find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website? \n" ); document.write( "

Algebra.Com's Answer #518004 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "p(looking for this website) = .95,   n = 4
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document.write( "P(x = 2) = binompdf(4,.95,2) = .0135 \n" );
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