document.write( "Question 72335: Solve the following 2 x 2 systems using substitutions
\n" ); document.write( "2x - 5y= 21
\n" ); document.write( "7x + 3y = 53
\n" ); document.write( "

Algebra.Com's Answer #51796 by elima(1433)\"\" \"About 
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2x - 5y= 21
\n" ); document.write( "7x + 3y = 53
\n" ); document.write( "Lets start with changing the first equation to x equals;
\n" ); document.write( "2x=21+5y
\n" ); document.write( "x=\"21%2F2\"+\"5y%2F2\"
\n" ); document.write( "now replace the x in the second equation;
\n" ); document.write( "7(\"21%2F2\"+\"5y%2F2\")+3y=53
\n" ); document.write( "Distribute the 7;
\n" ); document.write( "\"147%2F2\"+\"35y%2F2\"+3y=53
\n" ); document.write( "subtract \"147%2F2\"from both sides and add like terms;
\n" ); document.write( "\"35y%2F2\"+3y=53-\"147%2F2\"
\n" ); document.write( "get common denominators so you can add or subtract fractions;
\n" ); document.write( "\"35y%2F2\"+\"6y%2F2\"=\"106%2F2\"-\"147%2F2\"
\n" ); document.write( "\"41%2F2\"y=\"-41%2F2\"
\n" ); document.write( "multiply each side by the reciprocal of \"41%2F2\";
\n" ); document.write( "(\"2%2F41\")\"41%2F2\"y=\"-41%2F2\"(\"2%2F41\")
\n" ); document.write( "y=-\"82%2F82\"=-1
\n" ); document.write( "Now replace the y in the first equation with -1;
\n" ); document.write( "2x - 5(-1)= 21
\n" ); document.write( "2x+5=21
\n" ); document.write( "2x=16
\n" ); document.write( "x=8
\n" ); document.write( "so answer; y=-1, x=8
\n" ); document.write( ":)
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