document.write( "Question 859677: A rowing team rowed 50 miles while going with the current in the same amount of time as it took to row 25 miles going against the current. The rate of the current was 2 miles per hour. Find the rate of the rowing team in still water. \n" ); document.write( "
Algebra.Com's Answer #517889 by mananth(16946)![]() ![]() You can put this solution on YOUR website! rowing boat speed x mph with no current \n" ); document.write( "current speed 2 mph \n" ); document.write( " \n" ); document.write( "against current x - 2 mph \n" ); document.write( "with current x + 2 mph \n" ); document.write( " \n" ); document.write( "Distance against current 25 \n" ); document.write( "Distance with current 50 \n" ); document.write( "Time = same equate the time against with time with current \n" ); document.write( "t=d/r \n" ); document.write( "25 /(x- 2 )= 50 /(x+ 2 ) \n" ); document.write( "25 *(x+ 2 )= 50 *(x- 2 ) \n" ); document.write( "25 x + 50 = 50 x -100 \n" ); document.write( "25 x -50 x = -100 + -50 \n" ); document.write( "-25 x = -150 \n" ); document.write( "/ -25 \n" ); document.write( " x= 6 mph \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |