document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=859683>Question 859683</A>: <I><SPAN STYLE=\"word-break: break-all;\"> joan jogs 4km at a speed of 3km/hr. How long does she jog for? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #517888 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=517888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D = r*t\r<BR>\n" );
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document.write( "4 = 3*t\r<BR>\n" );
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document.write( "4/3 = t\r<BR>\n" );
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document.write( "1.3333 = t  (this is approximate)\r<BR>\n" );
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document.write( "t = 1.3333  (this is approximate)\r<BR>\n" );
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document.write( "So she jogged for roughly 1.3333 hours \r<BR>\n" );
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document.write( "Since 4/3 hrs = (4/3)*60 min = 240/3 min = 80 min, this means that she jogged for exactly 80 minutes.\r<BR>\n" );
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