document.write( "Question 859551: Solve the equation. Round to 2 decimal places if needed.\r
\n" ); document.write( "\n" ); document.write( "log(x)+log(3x-1)=1\r
\n" ); document.write( "\n" ); document.write( "I guess this one is confusing me because there isn't a base after the log. I know that I have to multiply (x)and(3x-1) because it is an addition problem, but not sure if I do that first or what to do.\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance for the help. \n" ); document.write( "

Algebra.Com's Answer #517818 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "no base 'after log' generally indicates base 10
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document.write( "log(x)+log(3x-1)=1
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document.write( "log(x)(3x-1)=1
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document.write( " x(3x-1) = 10
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document.write( " 3x^2 - x - 10 = 0
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document.write( " (3x + 5)(x - 2) = 0, 
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document.write( "          x = 2    (negative solution is an extraneous root) \n" );
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